find out no. of molecule in 29g of Cl atom.
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Answer:
Explanation:
mol chlorine atom
=35.5g
= 6.023×10^23 no.of atoms
35.5g chlorine contains 6.023×10^23 no.of atoms
Therefore,1g………………….6.023×10^23/35.5
=1.70×10^22 no.of atoms.
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