Chemistry, asked by clashwithash5238, 10 months ago

Find out normality of the solution obtained on mixin 20 ml n/2 hcl, 60ml n/10 h2so4 and 150 ml n/5 hno3

Answers

Answered by SrijanShrivastava
3

As; all the solutions mixed are acids and thus remain unreacted; thus:

N = [M₁V₁+M₂V₂+M₃V₃]÷(V₁+V₂+V₃)

N = [(20×1/2)+(60×1/10)+(150×1/5)]÷(20+60+150)

N = [10+6+30]÷(230)

N = 46÷230

N = 0•2 g-eqv L⁻¹

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