Find out normality of the solution obtained on mixin 20 ml n/2 hcl, 60ml n/10 h2so4 and 150 ml n/5 hno3
Answers
Answered by
3
As; all the solutions mixed are acids and thus remain unreacted; thus:
N = [M₁V₁+M₂V₂+M₃V₃]÷(V₁+V₂+V₃)
N = [(20×1/2)+(60×1/10)+(150×1/5)]÷(20+60+150)
N = [10+6+30]÷(230)
N = 46÷230
∴ N = 0•2 g-eqv L⁻¹
Similar questions