Find out oxidation number of chromium in K2Cr2O7 molecule.
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Answered by
8
Let oxidation number of Cr be x
2+2x-14=0
2x-12=0
2x=12
x=6
2+2x-14=0
2x-12=0
2x=12
x=6
Answered by
4
suppose O.N. of Cr is x
than
we can write
2+2x-14=0
2x=12
x=6
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