Find out pH of solution having 2×10^-3 moles of OH- ion in 2 lit solution
Answers
Answered by
68
Molarity of solution= 2×10^-3/2
= 10^-3 OH-
pOH=-log[OH-]
=-log(10^-3)
= 3
pH = 14 - pOH
= 14 - 3
= 11
= 10^-3 OH-
pOH=-log[OH-]
=-log(10^-3)
= 3
pH = 14 - pOH
= 14 - 3
= 11
Answered by
30
Answer:
11 is right ans
Explanation:
ok my answer will help you guys
Attachments:
Similar questions