Find out pH of solution having 2 x 10-3 moles of
OH ion's in 2 litre solution :-
(1) pH = 3
(2) pH = 3 + log2
(3) pH = 3 - log2 (4) pH = 11
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11
Answer:
Option 4
Explanation:
Concentration of oh- = no. Of moles / volume
= 2*10^-3/2
=10^-3
Poh = - log(oh-)
Poh = 3
PH = 14-3
Ph = 11
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3
Answer:4
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