Question

Find out ratio of time period of revolution of electron in 2nd orbit of Li2+ to 3rd orbit of He+

Answer 1

Answer:

2^5/3^5 (I am not sure about the answer .

Explanation:

We know that T is directly proportional to n^3/z^2.

So , T of Li    

      T of He

After putting n and z values on it we get 2^5/3^5

     

Answer 2

Given :

electron in 2nd orbit of L$i^2^+$

and , electron in 3rd orbit of H$e^+$  .

To find :

Ratio of the time period of the electron in 2nd orbit of L$i^2^+$ to the 3rd orbit of H$e^+$  .

Solution :

Time period of electron , T of any element in  orbit ∝ n³/z²

let the time period of electron in 2nd orbit of L$i^2^+$ be T1

and , the time period of electron in 3rd orbit of H$e^+$ be T2

Time period of electron in 2nd orbit of L$i^2^+$ , T1 ∝ ( 8 / 9 )

Time period of electron in 3rd orbit of H$e^+$ , T2 ∝ ( 27 / 4 )

Ratio = ( T1 / T2 ) = ( 8 * 4 ) / ( 27 * 9 )

         = 32 / 243

Ratio of the time period of the electron in 2nd orbit of L$i^2^+$ to the 3rd orbit of H$e^+$ = 32 / 243