Find out that which value of x is a solution to given equations.
b)2(4x+1)=42,(x=6,5,4)
please answer in process
Answers
Given-
Find out that which value of x is a solution to given equations.
b)2(4x+1)=42,(x=6,5,4)
please answer in process
Answer-
If x= 6
2(4x+1)=42
= 2(4 x 6 +1)=42
= 2(25)= 42
50=42
Which isnt correct so x=6 isnt right
If x= 5
2(4x+1)=42
=2(4 x 5+1)=42
= 2(20+1) = 42
2 (21)= 42
42=42
Here the LHS and rhs are balanced
So the right answer is x=5
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Answer:
first substituting ' 6 ' in x place
2(4x+1)=42 => 2( [ 4 × 6 ] + 1 ) = 42
=> 2 × 25 = 42
=> 50 = 42
It is not equal , So , it is not the solution
Now substitute ' 5 ' in x place
2(4x+1)=42 => 2 ( [ 4×5 ] + 1 ) = 42
=> 2 × 21 = 42
=> 42 = 42
It is equal , So , it is the solution
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