Question

FIND out the amplitude and the frequency from the equation of SHM y=5 sin 100pi t . The displacement has been expressed in meters and time in seconds

Answer 1

Just compare all the parameters with the standard equation.

Answer 2

The amplitude and the frequency of SHM is 5 meters and 5 Hz respectively.

Explanation:

The general equation of displacement of a particle is given by :

$y=A\ sin(\omega t)$

Given equation is :

$y=5\ sin(100\pi t)$

On comparing above two equations, we get :

Amplitude, A = 5 m

$\omega=100\pi$

Since, $\omega=2\pi f$

$2\pi f=100\pi$

f = 5 Hz

So, the amplitude and the frequency of SHM is 5 meters and 5 Hz respectively.

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Simple Harmonic motion

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