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Find the leagth of a rectangular field, if its area is 4125 m2 and the breadth is 55m Also find its perimeter​

Answer 1

Given :-

• Area of Rectangle = 4125m²
• Breadth of Rectangle = 55m

To Find :-

• Perimeter of the Rectangle

Solution :-

❏ For finding the Perimeter of the Rectangle we need Length and Breadth both , but in this question only Breadth is given, so we will find the length by applying " Area of Rectangle " as it is given area of Rectangle = 4125m²

➞ Area of Rectangle = Length × Breadth

➞ 4125 = Length × 55

➞ 4125 / 55 = Length

➞ 75m = Length

________________

⟾ Perimeter of Rectangle = 2 ( L + B )

⟾ Perimeter of Rectangle = 2 ( 75 + 55 )

⟾ Perimeter of Rectangle = 2 × 130

⟾ Perimeter of Rectangle = 260m

Thus, Perimeter of the Rectangle = 260m

________________

★ Additional Info :

Formulas Related to Rectangle :

• Perimeter of Rectangle = 2( l + b)
• Area = Length × Breadth
• Length = Area / Breadth
• Breadth = Area / Length
• Diagonal = √(l)² + (b)²

________________

Answer 2

★Given that:—

• → Breadth of a rectangular field = 55m
• → Area of rectangular field = 4125 sq.m

★To Find:—

• → Length of the rectangular field

★Solution:—

Let,

• → length of rectangular field = l
• → Breadth of rectangular field = b
• → Area of rectangular feild = A

†As Area of rectangle is given by:—

$\begin{gathered}Area = l \times b \end{gathered}$

‡Here

$\begin{gathered}4125 = l \times 55 \\ \\ l = \frac{4125}{55} \\ \\ \green{ \boxed{\boxed{ l = 75m}}}\end{gathered}$

Now perimeter of rectangle is given by:—

$\begin{gathered}P = 2(l + b) \end{gathered}$

Here:—

$\begin{gathered}P= 2(75 + 55) \\ \\ = 2 \times 130 \\ \\ \green{ \boxed{\boxed{ P = 260m}}}\end{gathered}$

$\pink{ \boxed{\boxed{@Vikramjeeth}}}$