Question

Find out the area of a triangle whose sides are 50 m. 78m. And 112m.

Answer 1

A=50 m
B=78 m
C=112 m
S=(A+B+C)
S=(50+78+112)
S=(128+112)
S=240m
Area of triangle = ^[S(s-a)(s-b)(s-c)]
= ^[240(240-50)(240-78)(240-112)]
=^ [ 240×190×162×128]
= 30,749.98 sq m