find out the area of an isosceles triangle whose base is 'a' and equal sides are of length 'b'.
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ANSWER;.....⛄
a/4√4b^2-a^2
MARK BRAINLIEST
a/4√4b^2-a^2
MARK BRAINLIEST
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Answer:
Step-by-step explanation:
1/2×b×[(a^2) - {(b -2)^2}]^1/2
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