find out the area of quadrilateral whose one diagonal is 12 cm long and length of perpendicular on it from the opposite vertices are 4cm and 5cm
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Step-by-step explanation:
Total area = sum of area of two triangles with common base as 12 cm and h1 as 4 cm h2 as 5 cm ]
A = 1/2*12*h1 + 1/2*12*h2
A = 1/2*12*4 + 1/2*12*5
A = 24 + 30 = 54 cm²
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