find out the area of rhombus whose one diagonal is 24cm and side is 13cm
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Answer:
Area of rhombus = 12×d1×d2
To find the length of the diagonal AC.
△OAB, ∠AOB=90∘; OB = 12 cm; AB = 13 cm.
AO2=AB−OB2=132−122=25
AO =25−−√= 5 cm
Therefore, length of one diagonal is 10 cm and the length of another diagonal is 24 cm.
Therefore, Area of Rhombus = 12×d1×d2=12×10×24 = 120 sq. cm.
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Answered by
1
Area of rhombus = 1\2*d1*d2
To find:
the length of the diagonal AC.
In triangle OAB , angleAOB=90degree
OB = 12 cm; AB = 13 cm.
AO^2=AB − OB^2
=132−122
=25
AO =root 25
= 5 cm
Therefore, length of one diagonal is 10 cm and the length of another diagonal is 24 cm.
Therefore, Area of Rhombus = 12*d1*d2 = 12×10×24 = 120 sq. cm.
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