Question

find out the area of total figure​

Answer 1

Answer:

420

Step-by-step explanation:

area of triangle is 180

so there are two big triangles there area will be 180+180 while the area of the rectangle will be 4×15. then add all that is

180+180+(15×4) which is equals to 420.

edit:sorry 180 is the sum of angles of a triangle not its area so 420 is wrong

Answer 2

Step-by-step explanation:

Given Question:-

Find the total area of the given figure?

Solution:-

The given figure consists of two figures they are ∆MDC triangle and ABCD is a Trapezium

Total area of the figure =Area of the triangle +Area of the Trapezium

Area of the triangle MDC:-

Base =DC=15 units

(since EBCD is a rectangle with EB=CD)

height=MN=6 units

Area of a triangle =(1/2)×base ×height sq.units

=>Area of ∆MDC=15×6/2

=>Area of ∆MDC=15×3=45 sq.units

Area of Trapezium ABCD:-

Parallel sides are AB=AE+EB=3+15=18 units

and CD=15 units

Distance between them=ED=4 units

(Since EBCD is a rectangle with BC=DE)

Area of a Trapezium=(1/2)(Distance between parallel sides)(Sum of parallel sides)

=>Area of the Trapezium=h(a+b)/2 sq.units

=>4(18+15)/2

=>4(33)/2

=>2(33)

=>66 sq.units

We have ,

Area of the triangle MDC=45 sq.units

Area of the Trapezium ABCD=66 sq.units

Area of the total given figure =

Area (∆MDC)+Area (Trapezium ABCD)

=>45+66

=>111 sq.units

Answer:-

Total area of the given figure =111 sq.units

Used formulae:-

• Area of a triangle=1/2×(bh) sq.units

Where, b is the base and h is the height of the triangle.

• Area of a Trapezium=1/2(h)(a+b) sq.units

where, a and b are two parallel sides of a Trapezium.

h is the distance between the two parallel sides of the Trapezium.