find out the area of total figure

Answers
Answer:
420
Step-by-step explanation:
area of triangle is 180
so there are two big triangles there area will be 180+180 while the area of the rectangle will be 4×15. then add all that is
180+180+(15×4) which is equals to 420.
edit:sorry 180 is the sum of angles of a triangle not its area so 420 is wrong
Step-by-step explanation:
Given Question:-
Find the total area of the given figure?
Solution:-
The given figure consists of two figures they are ∆MDC triangle and ABCD is a Trapezium
Total area of the figure =Area of the triangle +Area of the Trapezium
Area of the triangle MDC:-
Base =DC=15 units
(since EBCD is a rectangle with EB=CD)
height=MN=6 units
Area of a triangle =(1/2)×base ×height sq.units
=>Area of ∆MDC=15×6/2
=>Area of ∆MDC=15×3=45 sq.units
Area of Trapezium ABCD:-
Parallel sides are AB=AE+EB=3+15=18 units
and CD=15 units
Distance between them=ED=4 units
(Since EBCD is a rectangle with BC=DE)
Area of a Trapezium=(1/2)(Distance between parallel sides)(Sum of parallel sides)
=>Area of the Trapezium=h(a+b)/2 sq.units
=>4(18+15)/2
=>4(33)/2
=>2(33)
=>66 sq.units
We have ,
Area of the triangle MDC=45 sq.units
Area of the Trapezium ABCD=66 sq.units
Area of the total given figure =
Area (∆MDC)+Area (Trapezium ABCD)
=>45+66
=>111 sq.units
Answer:-
Total area of the given figure =111 sq.units
Used formulae:-
- Area of a triangle=1/2×(bh) sq.units
Where, b is the base and h is the height of the triangle.
- Area of a Trapezium=1/2(h)(a+b) sq.units
where, a and b are two parallel sides of a Trapezium.
h is the distance between the two parallel sides of the Trapezium.