Question

find out the base of the parallelogram whose area is 390cm² and the perpendicular is 26cm​

Answer 1

Given:

A parallelogram with

• Area = 390 cm²
• Perpendicular (Height) = 26 cm

What To Find:

We have to find the base of the given parallelogram.

Formula Needed:

$\bf {Area \: of \: Parallelogram = Base \times Height}$

Solution:

Using the formula,

$\sf {\implies Area \: of \: Parallelogram = Base \times Height}$

Substitute the values,

$\sf {\implies 390 \: cm^2 = Base \times 26 \: cm}$

Take 26 to LHS,

$\sf {\implies \dfrac{390}{26} = Base}$

Divide 390 by 26,

$\sf {\implies 15 \: cm = Base}$

∴ Thus, the base is 15 cm.

Verification:

Using the formula,

$\sf {\implies Area \: of \: Parallelogram = Base \times Height}$

Substitute the values,

$\sf {\implies 390 \: cm^2 = 15 \: cm \times 26 \: cm}$

Solve the RHS,

$\sf {\implies 390 \: cm^2 = 390 \: cm^2}$

∴ Hence, proved.

Answer 2

Given:

A parallelogram with

Area = 390 cm²

Perpendicular (Height) = 26 cm

What To Find:

We have to find the base of the given parallelogram.

Formula Needed:

$\bf {Area \: of \: Parallelogram = Base \times Height}$

Solution:

Using the formula,

$\sf {\implies Area \: of \: Parallelogram = Base \times Height}$

Substitute the values,

$\sf {\implies 390 \: cm^2 = Base \times 26 \: cm}$

Take 26 to LHS,

$\sf {\implies \dfrac{390}{26} = Base}$

Divide 390 by 26,

$\sf {\implies 15 \: cm = Base}$

∴ Thus, the base is 15 cm.

Verification:

Using the formula,

$\sf {\implies Area \: of \: Parallelogram = Base \times Height}$

Substitute the values,

$\sf {\implies 390 \: cm^2 = 15 \: cm \times 26 \: cm}$

Solve the RHS,

$\sf {\implies 390 \: cm^2 = 390 \: cm^2}$

∴ Hence, proved.