Math, asked by shadowthakur6247, 1 year ago

Find out the

c.i on rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years.

Answers

Answered by maheswarinilla21
12

Answer:

304

Step-by-step explanation:

P=5000 R%=4% per annum

1yr ----4% =200

1/2 yr ----2% = 100

(R%=2% per half year)

& 2% on 200= 4

Then 200+100+4 = 304

Answered by Syamkumarr
1

Answer:

The CI at 4% p.a. compound half-yearly for 1 \frac{1}{2} years is Rs. 306.04

Step-by-step explanation:

Given Principal(P) = Rs. 5000

Rate(r) = 4%pa

Time (t) = 1\frac{1}{2} years=\frac{3}{2} years

We need to find the Compound interest (CI)

We know that Amount (A) = P(1 + \frac{\frac{r}{2}}{100})²ⁿ

On substituting the values, we get

A = 5000*(1 + \frac{4}{200})²*^{\frac{3}{2}}

    = 5000*(1 + \frac{1}{50}

    = 5000 *  (\frac{51}{50}

    = 5000 * \frac{51}{50} *  \frac{51}{50} *  \frac{51}{50}

    = 5306.04

Therefore, CI = A - P

                      = 5306.04 - 5000

                      = 306.04

Therefore, the CI at 4% p.a. compound half-yearly for 1 \frac{1}{2} years is Rs. 306.04

   

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