find out the center of mass of a rod having uniformly distributed mass of M and length L lies at the middle point of rod.
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By symmetry of shape and uniform of mass
By symmetry of shape and uniform of mass
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Consider a rod of mass M and Lenth L.
let dx be a small part of the rod and its mass be dm.
s=M/L
so, dm= Mdx/L
Hence COM= integral of xdm/ integral of m
where x limits from 0 to L
com= 1/L X [x^2 /2] limit from 0 to L
By solving We Get,
COM=L/2
Hence COM Of a uniform rod of mass M and Length L lies at the middle point of rod.
let dx be a small part of the rod and its mass be dm.
s=M/L
so, dm= Mdx/L
Hence COM= integral of xdm/ integral of m
where x limits from 0 to L
com= 1/L X [x^2 /2] limit from 0 to L
By solving We Get,
COM=L/2
Hence COM Of a uniform rod of mass M and Length L lies at the middle point of rod.
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