Question

find out the change in velocity of object between 20s and 40s
a.90 m/s
b.4.5m/6. C.9 m/s d.150​

Answer 1

Answer:

Initial speed of the car is u.

Final speed of the car v=0

Let the retardation of the car be a.

Using v

2

−u

2

=2aS

Or 0−u

2

=2aS

⟹ S∝u

2

(for same a)

Given : S=40m u

′

=2u

∴

S

S

′

=

u

2

(u

′

)

2

=2

2

Or

40

S

′

=4

⟹ S

′

=160m

Explanation:

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