Find out the compound interest on ₹ 50,000 deposited in a bank at 15% annual rate after 2 year.
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Answers
Answer:
AnswEr :-
\implies \boxed{ \red{ \sf{C.I = 16125}}}⟹
C.I=16125
★ Given :-
Principal amount : Rs. 50000 /-
Time : 2 years
Interest rate : 15%
★ To Find :-
The compound interest
★ Solution :-
The formula of compound interest is,
\implies \boxed{ \red{ \sf{C.I = [P \times (1 + \dfrac{r}{100} )^{n} - 1]}}}⟹
C.I=[P×(1+
100
r
)
n
−1]
Where,
C.I = Compound Interest
P = Principal amount
r = Rate of interest
n = Time (in years)
\implies \sf \: C.I = [50000 \times (1 + \dfrac{15}{100} )^{2} - 1]⟹C.I=[50000×(1+
100
15
)
2
−1]
\implies \sf \: C.I = [50000 \times ( \dfrac{115}{100} )^{2} - 1]⟹C.I=[50000×(
100
115
)
2
−1]
\implies \sf \: C.I = [50000 \times ( \dfrac{13225}{10000} ) - 1]⟹C.I=[50000×(
10000
13225
)−1]
\implies \sf \: C.I = [50000 \times ( \dfrac{3225}{10000} ) ]⟹C.I=[50000×(
10000
3225
)]
\implies \sf \: C.I = [5 \times3225 ]⟹C.I=[5×3225]
\implies \boxed{ \red{ \sf{C.I = 16125}}}⟹
C.I=16125
Step-by-step explanation:
AnswEr :-
\implies \boxed{ \red{ \sf{C.I = 16125}}}⟹
C.I=16125
★ Given :-
Principal amount : Rs. 50000 /-
Time : 2 years
Interest rate : 15%
★ To Find :-
The compound interest
★ Solution :-
The formula of compound interest is,
\implies \boxed{ \red{ \sf{C.I = [P \times (1 + \dfrac{r}{100} )^{n} - 1]}}}⟹
C.I=[P×(1+
100
r
)
n
−1]
Where,
C.I = Compound Interest
P = Principal amount
r = Rate of interest
n = Time (in years)
\implies \sf \: C.I = [50000 \times (1 + \dfrac{15}{100} )^{2} - 1]⟹C.I=[50000×(1+
100
15
)
2
−1]
\implies \sf \: C.I = [50000 \times ( \dfrac{115}{100} )^{2} - 1]⟹C.I=[50000×(
100
115
)
2
−1]
\implies \sf \: C.I = [50000 \times ( \dfrac{13225}{10000} ) - 1]⟹C.I=[50000×(
10000
13225
)−1]
\implies \sf \: C.I = [50000 \times ( \dfrac{3225}{10000} ) ]⟹C.I=[50000×(
10000
3225
)]
\implies \sf \: C.I = [5 \times3225 ]⟹C.I=[5×3225]
\implies \boxed{ \red{ \sf{C.I = 16125}}}⟹
C.I=16125
Answer:
don't know the answer so sorry