Question

Find out the compound interest on Rs. 50,000/- deposited in a bank at 15% annual
rate after 2 years.​

Answer 1

Answer:

Solution:

P=Rs50,000

R=15%

T=2years

Amount=P(1+R/100)t

=50,000(1+15/100)²

=50,000×115/100×115/100

=66125

CI=A-P

=66125-50,000

=Rs16125

Answer 2

★ AnswEr :-

$\implies \boxed{ \red{ \sf{C.I = 16125}}}$

★ Given :-

• Principal amount : Rs. 50000 /-
• Time : 2 years
• Interest rate : 15%

★ To Find :-

• The compound interest

★ Solution :-

The formula of compound interest is,

$\implies \boxed{ \red{ \sf{C.I = [P \times (1 + \dfrac{r}{100} )^{n} - 1]}}}$

Where,

• C.I = Compound Interest
• P = Principal amount
• r = Rate of interest
• n = Time (in years)

$\implies \sf \: C.I = [50000 \times (1 + \dfrac{15}{100} )^{2} - 1]$

$\implies \sf \: C.I = [50000 \times ( \dfrac{115}{100} )^{2} - 1]$

$\implies \sf \: C.I = [50000 \times ( \dfrac{13225}{10000} ) - 1]$

$\implies \sf \: C.I = [50000 \times ( \dfrac{3225}{10000} ) ]$

$\implies \sf \: C.I = [5 \times3225 ]$

$\implies \boxed{ \red{ \sf{C.I = 16125}}}$