Question

Find out the difference between the simple interest and compound interest
for Rs. 3200/- at the rate of 12% annually in 2 years.​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

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GIVEN :-

• Principal amount = Rs. 3200
• Rate = 12%
• Time = 2 year

TO FIND :-

Compound interest - S.I = ?

SOLUTION :-

Simple interest :-

= >3200×12×2/100 = Rs. 768

Compound interest :-

$= > p[ {(1 + \frac{r}{100})}^{2} - 1] \\ \\ = > 3200[ {(1 + \frac{12}{100} )}^{2} - 1] \\ \\ = > 3200[ {(1 + \frac{3}{25} )}^{2} - 1] \\ \\ = > 3200[ { \frac{25 + 3}{25} )}^{2} - 1] \\ \\ = > 814.08 \: rupees$

So Compound interest - simple interest

=> 814.08 - 768 = 46.08 Rupees