Math, asked by sara7392, 8 months ago

find out the discriminant of the given quadratic equation​

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Answered by haripinninti17
0

Answer:

discriminant(∆)=bsquare (b2)- 4ac

=8-4x-6x1= 8+24=32

hope you got it

Answered by Anonymous
126

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Gɪᴠᴇɴ :

↦ x² + 2√2 x - 6 = 0

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Tᴏ Fɪɴᴅ :

↪ Discriminant of the given equation

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Fᴏʀᴍᴜʟᴀ ᴛᴏ ʙᴇ ᴜsᴇᴅ :

➳ D = B² - 4AC

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Sᴏʟᴜᴛɪᴏɴ :

→ D = B² - 4AC

→ D = (2√2)² - 4 × 1 × (-6)

→ D = 4 × 2 + 24

→ D = 8 + 24

→ D = 34

ᴅɪsᴄʀɪᴍɪɴᴀɴᴛ ᴏғ ᴛʜᴇ ᴇϙᴜᴀᴛɪᴏɴ ᴡɪʟʟ ʙᴇ 32

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Aᴅᴅɪᴛɪᴏɴᴀʟ ɪɴғᴏʀᴍᴀᴛɪᴏɴ :

Important properties of discriminant

⇒ If √b²-4ac = 0, then there is exactly one real solution.

⇒ If √b²-4ac ≻ 0, then there are exactly two real solutions.

⇒ If √b²-4ac ≺ 0, there are exactly two imaginary solutions.

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