find out the distance of the image when an object is placed on principal axis at a distance of 10cm infront of a concave mirror whose radios of curvature is 18cm
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Given : u=−10cm R=−8cm=2f f=−4cm
To find : v
Solution: From mirror formula
v1+u1=f1
v1−101=−41
v1=10/4−6
v=3−20cm
I hope it helps you my friend
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