Question

Find out the electron Polarizability of atoms from the given data. Relative permittivity of helium gas is 1.0000684 and if gas have 1.2 × 1026 atoms/m3. Also find out the radius of the atom.​

Answer 1

Explanation:

Given Find out the electron Polarizability of atoms from the given data. Relative permittivity of helium gas is 1.0000684 and if gas have 1.2 × 1026 atoms/m3. Also find out the radius of the atom.

• Relative permittivity ε r = 1.0000684
• Number of atoms in the gas N = 1.2 x 10^26 atoms / m^3
• Permittivity of free space εo = 8.854 x 10^-12 F /m
• So we have polarization P = εo (ε r – 1) E
•                              Also P = N α e E
• So we get N α e = εo (ε r – 1)
•          Or α e = εo (εr – 1) / N
•                      = 8.854 x 10^-12 (1.0000684 – 1) / 1.2 x 10^26
•                    = 8.854 x 10^-38 x 0.0000684
•                   = 5.046 x 10^-42 F / m^2
• Now electron polarizability will be
•                   So α e = 4 π εo R^3
•                       Or R = α e / 4 εo π
•                                 = 5.046 x 10^-42 / 4 x 8.854 x 10^-12 x 3.14
•                                   = 5.046 x 10^-30 / 111.20624
•                                   = 0.0453 x 10^-30 m
• Therefore radius of helium atom R = 0.0453 x 10^-30 m

Reference link will be

https://brainly.in/question/6536162

Answer 2

Answer:

upper answer is correct hope it helps you