Find out the energy of hydrogen atom in first ground state
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Here is your answer buddy,
In hydrogen atom energy of the first excited state is -3.4 eV. Find out the KE of the same orbit of hydrogen atom.
Hope this helps you. Have a nice day!!
In hydrogen atom energy of the first excited state is -3.4 eV. Find out the KE of the same orbit of hydrogen atom.
Hope this helps you. Have a nice day!!
Answered by
0
In first ground state n=1 so it's K.E =e/n
e=13.6ev
K.E =13.6
e=13.6ev
K.E =13.6
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