Question

Find out the equivalent weight of an acid, 1.248g of which requires exactly 0.2475g of potassium hydroxide for neutralization

Answer 1

Answer: -

Equivalent weight of the acid = 283.636 g

Explanation: -

Molar mass of potassium hydroxide KOH = 56.1 g/ mol

Mass of KOH =  0.2475 g.

Number of moles of KOH = $\frac{ 0.2475g}{56.1g/mol}$

                                           = 0.0044 mol

Number of equivalents of KOH = 0.0044 x Acidity of KOH = 0.0044 x 1 = 0.0044

1 equivalent of the acid will react with 1 equivalent of base according to the law of equivalents.

Number of equivalents of acid for complete neutralization = 0.0044

Equivalent weight of the acid = $\frac{Weight}{Number of equivalents}$

                  = $\frac{1.248g}{0.0044}$

                 = 283.636 g