Question

Find out the following

Answer 1

Hope it helps you :)

Answer 2

Given,

x - y = 2√3 and

xy = 1

To find,

x+y

Main solution :

(x-y)^2 = x^2 +y^2 -2xy

Substituting the values that we know :-

(2√3)^2 = x^2+y^2 -(2×1)

12 = x^2 + y^2 -2

x^2 + y^2 = 12 + 2

x^2 + y^2 = 14

Now,

(x+y)^2 = x^2 + y^2 + 2xy

Substituting the values that we know :-

(x+y)^2 = 14 + (2×1)

(x+y)^2 = 14 + 2

(x+y)^2 = 16

(x+y) = √16

(x+y) ± 4

Answer :- The value of (x+y) is ± 4.