Question

Find out the following in the electric circuit given figure (a)effective resistance of two 8 ohm resistor combination (b)current flowing through 4 ohm resistor (c) potential difference across 4 ohm resistance (d)power dissipated in 4ohm resistor (e) difference in ammeter reading,if any.

Answer 1

a.) 1/Rp= 1/8+1/8= 4 ohm.

b.) Current flowing through the circuit remains the same.

Effective Resistance= 4 ohm+ 4 ohm= 8ohm.

V=IR

8=I*8

I=1 A.

C.) V=IR

V=1*4= 4 V.

D.)P=VI

P=1*4

4 W.

E.) No there is no difference on the reading of the ammeter.