Find out the following in the electric circuit given in figure.
(i) Effective resistance of two 8 resistors in the combination
(ii) Current flowing through 422 resistor.
(iii) Potential difference across 412 resistance.
(iv) Power dissipated in 422 resistor.
(v) Difference in ammeter readings, if any
А
B
(A1
452
8V
8Ω 8Ω
KO
D
Answers
Answer:
Resistor,R1 = 4ohm
Resistor,R2 = 8ohm
Resistor,R3 = 8ohm
Potential Difference,d = 8volts.
Refer to the attachment for diagram
i)Since we know that R2 and R3 are in a Parallel combination,hence thier net resistance will be given by=>
1/Rp = 1/R2 + 1/R3
=>1/Rp = 1/8 + 1/8
=>1/Rp = 2/8
=>Rp = 4ohm.
hence the net resistance of the Parallel combination is 4 ohm.
ii)Now, since Rp and R1 are in series combination,hence their net resistance is given by-->>
Rn = Rp + R1
=>Rn = 4 + 4
=>Rn = 8ohm.
hence the net resistance of the whole circuit is 8 ohm.
Now, by using ohm 's law >
V= IR
=>I = V/R
=> I = 8/8
=>I = 1 ampere.
So , the current flowing through 5ohm resistor is 1 ampere.
iii)Now, again by Ohm's law>>
V=IR
=>V = 1 × 4
=>V = 4 v.
hence the potential difffernce across 4 ohm resistor is 4volts.
iv)We know that,
Power used = V × I
=>P = 4 × 1
=>P = 4 Watts.
Hence ,the power dissipated in 4 ohm resistor is 4 watts.
v) Same reading of both ammeters.
Since we know that the resistances Rp and R1 are in series combination hence same Current will flow through each resistor.Hence ammeter reading will be same.
Answer:
refer the attachment for your answer
