Question

Find out the following in the electric circuit in figure
i) Current flowing through 4Ω resistor
ii) Power dissipated in 4Ω resistor
iii) Difference in ammeter readings (A1 and A2), if any

Answer 1

(a) R= R1×R2/R1×R2 =( 8×8/8+8 )=4Ω

(b) I= RV = 4+( 8×8/8+8 )8 =8/8 =1A

(c) V=IR=1×4=4V

(d) P=I²R=1²×4=4W

(e) No difference, same current flows through each element in a series circuit