Question

Find Out the force of attraction between 2 objects of masses 45 kg and 1 kg respectively that are placed within a distance of 0.2 metres.

Answer 1

Given ,

• The masses of two objects are 45 kg and 1 kg

• Distance between two objects is 0.2 m

We know that , the force between two bodies is given by

$\boxed{ \sf{F = G \frac{ m_{1}m_{2}}{ {(r)}^{2} } }}$

Thus ,

$\sf \mapsto F = \frac{6. 6 \times {(10)}^{ - 11} \times 45 \times 1}{ {(0.2)}^{2} } \\ \\ \sf \mapsto F =3.3 \times 45 \times {(10)}^{ - 9} \\ \\ \sf \mapsto F =14.85 \times {(10)}^{ - 7} newton$

$\sf \therefore \underline{The \: force \: of \: attraction \: is \: 14.85 \times {(10)}^{ - 7} \: newton}$