Question

Find out the genotypes of the Progeny of the following crosses. 1)Aa❌aa​

Answer 1

$\tt\implies\underline{Genotypically\:\red{Aa}, phenotypically \: \green{A}}$

$\bf{\underline{\underline{Aa \: ❌ \: aa}}}\: - \sf When \: a \: cross \: is \: made \: between \: AA \: \\ \sf and \: aa, \: the \: F1 \: progeny \: is \: phenotypically \: A, \: \\ \sf Genotypically \: Aa, \: as \: per \: the \: Mendel’s \: Law \: of \: \\ \sf dominance.$

Answer 2

Two genotype will be possible for this one is Aa and other is  aa

Explanation:

• If we cross Aa× aa we can get two genotype
• From Aa genotype we can get two type of gamete. one is A and other is a
• from aa genotype we get only one kind of gamete that is a.
• Put them on Punnet square to determine possible genotype

                              A               a

                a         Aa               aa

           

                a          Aa              aa

• by drawing punnet square we  found that 2 genotype is possible by crossing Aa× aa. one is Aa and other is aa
• Two different phenotype is possible. Aa is a heterozygous dominant and aa is homozygous recessive.