Find out the given cell is spontaneous or nonspontaneous H2/H^+
Answers
The complete question is,
Find out the given cell is spontaneous or nonspontaneous H2/H^+ (P1) || H^+/H2 (P2) if P1 > P2
Given:
H2/H^+ (P1) || H^+/H2 (P2) if P1 > P2
To find:
Find out the given cell is spontaneous or nonspontaneous H2/H^+ (P1) || H^+/H2 (P2) if P1 > P2
Solution:
From given, we have,
H2/H^+ (P1) || H^+/H2 (P2) if P1 > P2
we use the formula,
E_{cell} = E0 - 0.0257/n ln Q
we use ln Q = 2.303 × log Q
so we have,
E_{cell} = E0 - 0.0257/n (2.303 × log Q)
∴ E_{cell} = E0 - 0.0592/n log Q
from given, we have,
Q = P1/P2
∴ E_{cell} = E0 - 0.0592/n log P1/P2
as (P1 > P2)
∴ E_{cell} = 0 - (+ve)
∴ E_{cell} = -ve
we use the formula,
ΔG = -nfE
as E is negative, so we get,
ΔG = +ve
The value of ΔG indicates whether the reaction is spontaneous or nonspontaneous.
A positive ΔG represents a nonspontaneous reaction.
∴ H2/H^+ (P1) || H^+/H2 (P2) if P1 > P2 is a nonspontaneous reaction.