find out the hcf of two consecutive numbers
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Let us take two consecutive numbers as 5 and 6. The two numbers have 1 as a common factor and nothing else. Hence 1 is the HCF. This proves that the HCF of any two consecutive numbers is always a one.
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Let two consecutive number
first is x
second is (X+1)
now for example x is any no. you choose 1,2,3,4....
X=5
X+1=6
now apply prime factorisation .
we find 5=5×1
6=2×3×1
common factor in two terms is 1.
that term is common in prime factorisation is HCF and common term is one
HCF of two consecutive number is one .
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