Question

Find out the heat developed in 5 minute by a device of resistance 1150 ohm working under 230v ?
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Answer 1

Answer:

all go to the last time you

Answer 2

Answer:

Hi here's your answer

Explanation:

5min = 300 sec

$H=I^{2} \frac{R}{t}$

lets find I

I = V/r

I = 230/1150

I = 0.2 A

now lets substitute in the formula,

$[0.2]^{2} * \frac{1150}{300}$

$0.04 * 3.83$

H = 0.15 J

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