Question

Find out the least number which when divided by 8, 12,16, 24 or 32 leaves remainder 5 in each case?

Answer 1

the required number is LCM of the numbers+5
now, LCM of 8,12,16,24,32 :
8= 2^3
12= 2^2 * 3
16= 2^4
24 = 2^3 * 3
32 = 2^5
thus LCM is 2^5* 3= 96
the required number is 96+5= 101