Question

find out the mass of 112L Ammonia

Answer 1

Given volume of Ammonia = 112 L

We know , at  STP, a mole of any gas has a volume of 22.4 litres

Therefore, Number of moles = volume at STP/ 22.4l

n =  112/22.4

n = 112 × 10 / 112 ×2

n = 10 / 2

n = 5

Therefore we have 5 moles of Ammonia

Molar mass of Ammonia = NH₃

= 1 × 14 + 3×1

= 14 + 3

= 17 amu

Number of moles = Gram Molecular Mass (g)/Molar Mass

n=X/molar mass

5=X/17

X= 5×17

X=85

therefore mass of ammonia is 85 grams