Question

find out the mass of CaO formed when 65.6gm of Ca(NO3)2 is heated​

Answer 1

Answer:

22.34g

Explanation:

2Ca(NO3)2 = 2CaO + 4NO2 + O2

no.of moles of calcium nitrate =

65.6g/164.08g/mol

= 0.399mol

now, from stoichiometry of the reaction,

2mol of Ca(NO3)2 =2mol of CaO

hence,0.399mol of Ca(NO3)2 = 0.399mol of CaO

=( 0.399mol)×(56g/mol) = 22.34g