Question

find out the mass of H2So4 in 150ml of 1/7 normal H2So4 ​

Answer 1

Answer:

normality= 1/7

mass of H2SO4 = 98

equivalent weight of H2SO4 = 49

g.eq= gram equivalent

= given mass/ equivalent weight

now check the image attached.

Explanation:

hope it helps

Answer 2

The mass of $H_2SO_4$ in 150ml of 1/7 normal

Explanation:

Normality of a solution is defined as the number of gram equivalents of solute dissolved per Liter of the solution.

$Normality=\frac{number of gram equivalents\times 1000}{\text {Volume in ml}}$

$Normality=\frac{n\times 1000}{V_s}$

where,

n= gram equivalents of solute

$Equivalent mass=\frac{\text{Molecular mass}}{basicity}=\frac{98}{2}=49$

gram equivalents=$\frac{\text{Given mass}}{\text{Equivalent mass}}=\frac{x}{49}$

$V_s$ = volume of solution in ml= 150 ml

$\frac{1}{7}=\frac{xg\times 1000}{49g/eq\times 150ml}$

$x=7g$

Thus 7 grams of $H_2SO_4$ in 150ml of 1/7 normal

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