Question

Find out the mass of magnesium carbonate that will react with 49 gram of sulphuric acid .

Answer 1

Answer:

Explanation:

MgCO3 + H2SO4 = MgSO4 + CO2 + H2O

moles of sulphuric acid = 49/98

= 0.5

1 mole of MgCO3 reacts with 1 mole of H2SO4

so 0.5 mole of H2SO4 reacts with 0.5 mole of MgCO3

mass of MgCO3  = 0.5*84

= 42 g