Find out the mass of unreacted oxygen when a mixture of 100g of O2 and
24g of CH, gas is ignited.
Answers
Answer:
ANSWER
24g
2mol
2C(s)
+
32g
1mol
O
2
→
56g
2mol
2CO(g)
Let carbon be completely consumed.
24g carbon give 56 g CO.
Let O
2
is completely consumed.
∵ 32 g O
2
give 56 g CO.
∴ 96 g O
2
Will give
32
56
×96gCO=168gCO
Since, carbon gives least amount of product, te.,56 g CO or 2 mole CO, hence carbon will be the limiting reactant.
∴ Excess reactant is O
2
.
Amount of O
2
used =56−24=32g
Amount of O
2
left =96−32=64g
32g O
2
react with 24 g carbon
∴ 96 g O
2
will react with 72g carbon.
Thus, carbon should be taken 72g so that nothing is left at the end of the reaction.
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