Find out the mass of Uranium required per day lo generrequired per day to generate 10 MW power from the fision of uranium 235
Answers
Answer:
The amount of Uranium 235 required per day to generate 10MW = 10.58 g
Explanation:
The nuclear reaction of Uranium 235,
⇒ fission product + no. of neutrons + energy (≈ 200 MeV)
To convert eV into Joules
1 eV = 1.602 x J
Therefore, 1 atom of Uranium produces
= 200 MeV x 1.602 x
= 3.204 x J
From the conversion formula
1 joule = 1 watt - sec
1 watt - hour = 3600 J
Given that 10 MW generation per day
It should generate 10 MW x 24 watts-hour
= 240 MWh
Converting 240 Wh into joules gives
240 MWh = 8.64 x J
The number of atoms responsible for producing8.64 x J of energy is given by ,
no. of atoms = total energy produced/energy of 1 atom of
= 8.64 x /3.204 x
= 2.697 x
Number of moles present in the given no. of atoms is given by
no. of moles = total no. of atoms/ avagadro number
= 2.697 x / 6.022 x
= 0.45 mol
Therefore, mass of the substance is given by
mass of substance = no. of moles x mass of 1 mole
= 0.45 x 235
= 10.58 g
So, the amount of required per day to generate 10MW = 10.58 g
PLEASE MARK AS BRAINLIEST