Question

Find out the mass of uranium required per day to operate 0.95 MW nuclear power plant using

Answer 1

Answer:

Mass of Uranium required per day is 0.112 g

Explanation:

Binding energy of Uranium Nuclei is given as

$BE = 1783 MeV$

here we know that this is binding energy of 1 atom of Uranium

So due to N atoms the total energy will be

$E = N(1783 \times 10^6 \times 1.6 \times 10^{-19})$

$E = 2.85 \times 10^{-10}N J$

now we know that this is energy required per day

so total power per day is given as

$P = \frac{2.85 \times 10^{-10} N}{24 \times 3600}$

$P = 3.3 \times 10^{-15} N$

Now we have

$0.95 \times 10^6 = 3.3 \times 10^{-15} N$

$N = 2.88\times 10^{20}$

now total number of moles required is

$n = \frac{N}{N_a}$

$n = 4.78 \times 10^{-4}$

now mass of the Uranium required is

$M = moles \times (235 g/mol)$

$M = (4.78 \times 10^{-4})(235)$

$M = 0.112 g$

#Learn

Topic : Binding Energy

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Answer 2

Answer:

m=1 gram

Explanation:

refer attachment for solution