Find out the minimum force that must be applied
on the block vertically downward so that block does
not move.
-
10kg
10 kg
100N
100 N
A = 0.5
ob on
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Given:
Refer the image.
To Find:
Minimum force that must be applied on the block vertically downward so that block does not move.
Solution:
100−fs=0
=> fs=100……….(1)
F+10g=N⇒N=100+F…………(2)
Now 0≤fs≤μN
100≤0.5N
100≤0.5[100+F]
200≤100+F
F≤100N
Hence, Minimum F = 100 N
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