Question

find out the mole in 56 g nitogen at stp ​

Answer 1

HEY MATE HERE IS YOUR ANSWER >>>>

CALCULATION OF MOLE >>

∵28 g OF $N_{2}$ OCCUPIES = 1 MOL OF $N_{2}$

∵56 g of $N_{2} = \frac{1}{28}*56 = 2$ mole of $N_{2}$

Answer 2

=》》》Hi freind this question is based upon the concept of mole concept

Here is your answer dear mate

=》》♧1 mole of N2 = 28 grams = 22.4 L volume is occupied by it

28 g = 1 mole

so,

56 g = 56/28 = 2 moles.

1 mole occupies volume = 22.4 L

so,

2 moles will occupy = 22.4 x 2 = 44.8 L.✔️

●hope this helps you freind please mark me as brainliest dear freind

---------thank you---------