Math, asked by Yasashwi7033, 1 year ago

Find out the nhi and 12th term of the series:3/5,1/5,(-)1/5,(-)3/5......

Answers

Answered by chetanapadol1234

0

Answer:

tn=1/5n+2/5

t12=59/5

Step-by-step explanation:

1st term is a & common difference is d

d= 1/5

tn=a+(n-1)d

t12=3/5+(12-1)1/5

=3/5+56/5

= 59/5

tn=3/5+(n-1)1/5

=3/5+1/5n-1/5

=1/5n+2/5

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