Question

find out the no.of molecules in ome drop of water if it's volume is 0.18 ml?​

Answer 1

According to mole concept we know that gram molecular weight of any compound consists of Avogadro number of molecules.

This implies that 18 grams of water consists 6.023 x 1023 molecules of water.

18 grams = 6.023 x 1023 molecules

0.18 grams = ?

$= (0.18 × 6.023 × {10}^{23}) \div 18 = 6.023 \times {10}^{21}$

Therefore, 6.023 × (10) power of 21 molecules of water is present in one drop

Hope this helps you!

Mark as the brainlliest answer..