find out the number electron present in last shell of an atom having atomic number 15
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@#(_(_) _+_-_(#) 3+_) _-_) ₹(_+₹) _-_((₹+_(_+_(+_(₹(_+_) (_+&(_(_(&+(_(_)
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THE NUMBER OF ELECTRONS PRESENT IN LAST SHELL OF AN ATOM HAVING ATOMIC NUMBER 15(PHOSPHOROUS) IS 3 OR 5.....
THE ELECTRONIC CONFIGURATION IS
1s2 2s2 2p6 3s2 3p3
HERE ACCORDING TO ELECTRONIC CONFIGURATION THE VALENCY IS 3
BUT IT CAN EXHIBIT 5 VALENCY DUE TO ITS PHYSICAL PROPERTIES
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