Question

find out the number of atoms of oxygen in 9 moles of potassium permanganate​

Answer 1

Answer:

$9$ moles of potassium permanganate contain $2.16792$ × $10^{25}$ oxygen atoms.

Explanation:

From the formula, we get that,

one mole of potassium permanganate contains four moles of oxygen atoms.

So,

number of moles of oxygen atom in $9$ moles of $KMnO_{4}$,

        n $=$ $\frac{9 mol}{1 mol}$ × $4$ mol

        n $=$ $36$ mol of oxygen atoms

We know,

 $1$ mol of oxygen atom $=$ $6.022$×$10^{23}$ atoms

$36$ mol of oxygen atoms $=$ $36$×$6.022$×$10^{23}$

                                        $=$ $2.16792$ × $10^{25}$ atoms

∴ number of oxygen atoms $=$ $2.16792$ × $10^{25}$ atoms