Question

Find out the number of atoms present in 90 g of water.

Hints: atomic mass of H =1, O =16​

Answer 1

Answer:

6.023×10 to the power 24

Answer 2

Answer:

n=w/m=18/90=0.2 moles   m- molar mass     w- weight

total no of atoms= moles×avogadro number

=0.2×6.023×10²³ atoms

=12.046×10²² atoms

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